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If x : y = 3 : 1, then x^3 – y^3 : x^3 + y^3 = ?

If x : y = 3 : 1, then x3 – y3 : x3 + y3 = ?
a) 13 : 14
b) 14 : 13
c) 10 : 11
d) 11 : 10

Answer: a
Explanation:
$$\eqalign{ & x:y = 3:1 \cr & \frac{x}{y} = \frac{3}{1} \cr & \frac{{{x^3} – {y^3}}}{{{x^3} + {y^3}}} \cr & \Rightarrow \frac{{{y^3}\left( {\frac{{{x^3}}}{{{y^3}}} – 1} \right)}}{{{y^3}\left( {\frac{{{x^3}}}{{{y^3}}} + 1} \right)}} \cr & {\text{taking }}{{\text{y}}^3}{\text{ common}} \cr & {\text{ = }}\frac{{\frac{{{x^3}}}{{{y^3}}} – 1}}{{\frac{{{x^3}}}{{{y^3}}} + 1}} \cr & \Rightarrow \frac{{27 – 1}}{{27 + 1}} \cr & \Rightarrow \frac{{26}}{{28}} \cr & \Rightarrow \frac{{13}}{{14}} \cr} $$

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