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If the average of m numbers is n^2 and that of n numbers is m^2 , then the average of (m + n) numbers is

If the average of m numbers is n2 and that of n numbers is m2 , then the average of (m + n) numbers is
a) m – n
b) mn
c) m + n
d) $$\frac{m}{n}$$

Answer: b
Explanation: Sum of m numbers = mn2
Sum of n numbers = nm2
Average of (m + n) numbers
= $$\frac{mn(m + n)}{(m + n)}$$
= mn

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