a) 5
b) 2q
c) 5p
d) 4r
Answer: c
Explanation:
$$\eqalign{
& p = k,\,q = 2k,\,r = 4k \cr
& \sqrt {5{p^2} + {q^2} + {r^2}} \cr
& = \sqrt {5{k^2} + {{\left( {2k} \right)}^2} + {{\left( {4k} \right)}^2}} \cr
& = \sqrt {5{k^2} + 4{k^2} + 16{k^2}} \cr
& = \sqrt {25{k^2}} \cr
& = 5k \cr
& = 5p. \cr} $$
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