a) 252
b) 250
c) 1001
d) 1089
Answer: c
Explanation: The situation is similar to placing 10 identical balls among 5 distinguishable boxes, where a box may have zero or more balls in it.
This case can be represented as arranging ten balls and (5 – 1) four walls in the single row, which can be done in 14C4 ways. (The balls placed between every successive pair of walls belong to one group) 14C4 = 1001 ways.
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