Farah got married 8 years ago, Today her age is $$1\frac{2}{7}$$ times her age at the time of her marriage. At present her daughter’s age is one-sixth of her age. What was her daughter’s age 3 years ago ?
a) 4 Years
b) 3 Years
c) 6 Years
d) Cannot be determind
Answer: b
Explanation: Let Farah’s age 8 years ago be x years.
Then , her present age = (x + 8)
$$\eqalign{
& x + 8 = \frac{9}{7}x \cr
& 7x + 56 = 9x \cr
& 2x = 56 \cr
& x = 28 \cr} $$
∴ Farah’s age now
= (x + 8) years
= (28 + 8) years
= 36
Her daughter’s age now
=$$\left( {\frac{1}{6} \times 36} \right)$$ years
= 6 years
Her daughter’s age 3 years ago
= (6 – 3) years
= 3 years
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