a) 20
b) 21
c) 28
d) 32
Answer: c
Explanation: Let Ajit’s average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings.
$$\eqalign{
& 9x + 100 = 10 \times \left( {x + 8} \right) \cr
& 9x + 100 = 10x + 80 \cr
& x = 100 – 80 \cr
& x = 20 \cr
& {\text{New}}\,{\text{average}} = \left( {x + 8} \right) \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 28\,{\text{runs}} \cr} $$
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