a) 36 kmph
b) 26 kmph
c) 63 kmph
d) 35 kmph
Answer: a
Explanation: Let speed of the 2nd train is S m/sec.
60 kmph $$ = \frac{{60 \times 5}}{{18}} = \frac{{50}}{3}$$ m/sec.
As trains are traveling in same distance, Then Relative distance,
$$\eqalign{
& = \frac{{60 \times 5}}{{18}} = \frac{{50}}{3} \cr
& \frac{{50}}{3} – S = \frac{{120}}{{18}} \cr
& \Rightarrow \frac{{50 – 3S}}{3} = \frac{{20}}{3} \cr
& \Rightarrow 50 – 3S = 20 \cr
& \Rightarrow 3S = 50 – 20 \cr
& \Rightarrow 3S = 30 \cr
& \therefore S = 10\,\,{\text{m/sec}} \cr} $$
Or, Speed of the 2nd train = $${\text{10}} \times \frac{{18}}{5}$$ = 36 kmph.
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