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A tractor having weight as 1500 KGF is brought to a speed of 10 KMPH in 10 seconds by applying a uniform acceleration. Calculate initial fore on tractor.

a) 416.67 N
b) 372.98 N
c) 747.8 N
d) 219.84 N

Answer: a
Explanation: Acceleration: \(\frac{v-u}{t}=\frac{10*5}{18}-\frac{0}{10}=\frac{50}{18*10}=\frac{5}{18}\)
Initial Force = ma
= 1500*\(\frac{5}{18}\)
= 416.67 N.

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