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A tractor has belt speed of 1000 m/min at normal engine speed. A feed mill has a recommended speed of 2100 rev/min. Find the size of pulley, needed on the Feed mill.

a) 14.28 cm
b) 12.14 cm
c) 19.11 cm
d) 15.16 cm

Answer: d
Explanation: Belt speed (V) = 1000 m/min
V = πDn
πDn = 1000
D = \(\frac{1000}{πn}=\frac{1000}{π*2100}\)=0.1516 m
Required size of pulley = 15.16 cm.

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