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A soldier fired two bullets at an interval of 335 seconds moving at a uniform speed V1. A terrorist who was running ahead of the soldier in same direction, hears the two shots at an interval of 330 seconds. If the speed of sound is 1188 km/h, then who is the faster and how much?

A soldier fired two bullets at an interval of 335 seconds moving at a uniform speed V1. A terrorist who was running ahead of the soldier in same direction, hears the two shots at an interval of 330 seconds. If the speed of sound is 1188 km/h, then who is the faster and how much?
a) Soldier, 22 km/h
b) Terrorist, 25 km/h
c) Soldier, 18 km/h
d) Terrorist, 20 km/h

Answer: c
Explanation: $$\frac{{{\text{Speed }}\,{\text{of }}\,{\text{sound}}}}{{{\text{Relative speed of soldier and terrorist}}}} = $$         $$\frac{{{\text{Time }}\,{\text{taken}}}}{{{\text{Difference }}\,{\text{in }}\,{\text{time}}}}$$
$$\frac{{1188}}{{\text{S}}} = \frac{{330}}{5}$$
Soldier = 18 km/h

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