Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

A pair of bullocks exert 100 kg pull at 30° to the horizontal while making a V-shape furrow 15 cm wide and 5 cm deep. The speed of ploughing is 3 KMPH. What is the unit draft on the implement and horsepower developed by the bullocks?

a) 2.31 kg/cm2; 0.96 HP
b) 2.11 kg/cm2; 0.86 HP
c) 2.56 kg/cm2; 0.98 HP
d) 3.11 kg/cm2; 0.76 HP

Answer: a
Explanation:
168
Cross sectional area = \(\frac{1}{2}\)*b*h = \(\frac{1}{2}*15*5\) = 37.5cm2
Unit draft (Du) = \(\frac{P cosθ}{A} = \frac{100*cos30°}{37.5}\) = 2.31kg/cm2
Power = \(\frac{[Draft (kg)*S (\frac{m}{s})]}{75}\) hp = \(\frac{[P cos30°*3*1000]}{75*60*60}\)=0.96 HP.

Join The Discussion