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A man sells chocolates which are in the boxes. Only either full box or half a box of chocolates can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially?

a) 2
b) 3
c) 4
d) 3.5

Answer: b
Explanation: The best way to go through the options
Let there are initially 3 boxes then,
1st customer gets = $$\frac{3}{2}$$ + $$\frac{1}{2}$$ = 2
Remaining boxes = 3 – 2 = 1
2nd customer = $$\frac{1}{2}$$ + $$\frac{1}{2}$$ = 1
Option ‘b’ is correct.

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