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A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart.

a) 500, 300
b) 200, 400
c) 400, 200
d) 300, 500

Answer: c
Explanation: Let X be the cost of horse and Y be the cost of the cart.
10% of loss in selling horse = 20% of gain in selling the cart.
$$\frac{{10}}{{100}} \times {\text{X}}$$ = (20 × 100) × Y
X = 2y ————–(1)
5% of loss in selling horse is 10 more than the 5% gain in selling the cart.
Therefore, $$\frac{5}{{100}} \times {\text{X}} – 10 = \frac{5}{{100}} \times {\text{Y}}$$
5X – 1000 = 5Y
Using equation (1),
10Y – 1000 = 5Y
5Y = 1000
Y =200
X = 400
CP of Horse = Rs. 400
CP of the Cart = Rs. 200

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