A leather belt 100 mm wide and 10 mm thick with a safe permissible stress of 1.5 MPa is used for transmitting a maximum power of 15 KW. If the density of belt material is 1 g/cm³, the velocity of belt for maximum power transmission will be ________
a) 22.36 m/s
b) 34.13 m/s
c) 24.98 m/s
d) 12.12 m/s

Answer: a
Explanation: Area = 100*10*20^-6 = 10^-3m²
Tmax = Pmax * Area
= 1.5 * 10 * 10^-3
Tmax = 1500 N
M = ρ*area
= 1000*10^-3 = 1 kg/m
For maximum transmission
Tmax = 3T_c
Tmax= 3mv²
V = \(\sqrt{\frac{Tmax}{3m}} = \sqrt{\frac{1500}{3}} \)
V = 22.36 m/s