a) 15 days
b) 16 days
c) 18 days
d) 20 days
Answer: a
Explanation:
A is thrice good workman as B.
A = 3B
Let B can finish work in X days, then A will finish same work in (X – 40) days alone
BX = 3B × (X – 40)
X = 60 days
B can finish work in 60 days, then A can finish the work in 20 days.
One day work of B = $$\frac{1}{{60}}$$
One day work of A = $$\frac{1}{{20}}$$
One day work of (A+B) =
$$\frac{1}{{60}} + \frac{1}{{20}} \Rightarrow \frac{{1 + 3}}{{60}} \Rightarrow \frac{1}{{15}}$$
They can finish work together in 15 days
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