a) $$\frac{{124}}{{13}}$$ days
b) $$\frac{{113}}{{13}}$$ days
c) $$\frac{{108}}{{13}}$$ days
d) $$\frac{{120}}{{13}}$$ days
Answer: d
Explanation: Given,
A is 60% more efficient of B Means,
$$\eqalign{
& {\text{A}} = {\text{B}} + 60\% \,{\text{of B}} \cr
& {\text{A}} = {\text{B}} + \frac{{60{\text{B}}}}{{100}} \cr
& {\text{A}} = \frac{{100{\text{B}} + 60{\text{B}}}}{{100}} \cr
& {\text{A}} = \frac{{160{\text{B}}}}{{100}} \cr
& {\text{A}} = \frac{{8{\text{B}}}}{5} \cr} $$
A can complete whole work in 15 days. So,
One day work of A = $$\frac{1}{{15}}$$
One day work of A = $$\frac{{8{\text{B}}}}{5}$$ = $$\frac{1}{{15}}$$
One day work of B = $$\frac{5}{{120}}$$ = $$\frac{1}{{24}}$$
One day work, (A + B) = $$ \frac{1}{{15}} + \frac{1}{{24}}$$
One day work, (A + B) = $$\frac{{24 + 15}}{{360}}$$ = $$\frac{{39}}{{360}}$$
Time taken to finish the work by A and B together = $$\frac{{360}}{{39}}$$ = $$\frac{{120}}{{13}}$$ days
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