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A hemisphere of lead of radius 6 cm is cast into a right circular cone of height 75 cm. The radius of the base of the cone is :

a) 1.4 cm
b) 2 cm
c) 2.4 cm
d) 4.2 cm

Answer: c
Explanation: Let the radius of the cone be R cm
$$\eqalign{ & \frac{1}{3}\pi \times {R^2} \times 75 = \frac{2}{3}\pi \times 6 \times 6 \times 6 \cr & {R^2} = \left( {\frac{{2 \times 6 \times 6 \times 6}}{{75}}} \right) \cr & {R^2} = \frac{{144}}{{25}} \cr & {R^2} = \frac{{{{\left( {12} \right)}^2}}}{{{{\left( 5 \right)}^2}}} \cr & R = \frac{{12}}{5} \cr & R = 2.4\,cm \cr} $$

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