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A four-stroke diesel engine operating at 1200 rpm uses 0.1 kg of fuel in 5 minutes and has the brake specific fuel consumption equals to 0.1910 kg\BHP\h. Calculate the torque developed.

a) 6.5 kg-m
b) 8 kg-m
c) 7.5 kg-m
d) 5 kg-m

Answer: c
Explanation: N = 1200/2 = 600
BHP = 2πpT/4500
= 0.837T
Break Sp. Fuel Consumption = 0.1*60/0.837T*5
0.1910 = 0.1/0.837T*5
T=7.5 kg-m.

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