A four-stroke diesel engine operating at 1200 rpm uses 0.1 kg of fuel in 5 minutes and develops a torque of 7.5 kg-m. What is the brake specific fuel consumption.
a) 0.2810 kg/BHP/h
b) 0.1910 kg/BHP/h
c) 0.1886 kg/BHP/h
d) 1.1010 kg/BHP/h
Answer: b
Explanation: BHP = \(\frac{2πpT}{4500} = \frac{2π*600*7.5}{4500} \)
BHP = 6.28 hp
Brake specific fuel consumption = \(\frac{0.1}{6.28}*\frac{60}{5}\) = 0.1910 kg/BHP/h
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