a) 2
b) 3
c) 10
d) 11
Answer: c
Explanation:
$$\eqalign{
& {\text{we}}\,{\text{first}}\,{\text{need}}\,{\text{to}}\,{\text{find}}\,{\text{the}}\,{\text{HCF}}\,{\text{of}}\,{\text{44,66,110}}. \cr
& 44 = 2 \times 2 \times 11 \cr
& 66 = 2 \times 3 \times 11 \cr
& 110 = 2 \times 5 \times 11 \cr
& {\text{HCF}} = 2 \times 11 = 22 \cr
& {\text{Then,}}\,{\text{the}}\,{\text{required}}\,{\text{numbers}}\,{\text{of}}\,{\text{rows}}, \cr
& = { {\frac{{44}}{{22}}} + {\frac{{66}}{{22}}} + {\frac{{110}}{{22}}} } \cr
& = 10 \cr} $$
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