Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

A does half as much work as B in one -sixth of the time.If together they take 10 days to complete a work, how much time shall B take to do it alone?

a) 13.33 days
b) 20 days
c) 30 days
d) 40 days

Answer: d
Explanation: Given,
$${\text{A}} \times \frac{1}{6} = {\text{B}} \times \frac{1}{2}$$
A = 3B
Given they together complete the work in 10 days
So, One Day’s work of,
(A + B) = $$\frac{{100}}{{10}}$$ = 10%
(3B + B) = 10%
4B = 10%
one day work of B = $$\frac{{10}}{4}$$ = 2.5%
B can complete 100% work in = $$\frac{100}{2.5}$$ = 40 days

Join The Discussion