A counter shaft of engineering workshop is being driven by electric motor with the help of canvas belt and pulley arrangement such that the speed of belt is 600 m/min and it transmits 50 KW. What will be the difference between tensions on either side of the belt?

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a) 10000
b) 100
c) 5000
d) 50

Answer: c
Explanation: V = 600*10/60 = 10 m/s
P = (T1-T2) * V
50000 = (T1-T2) * 10
T1 – T2 = 5000