A capillary tube has a diameter of 3 mm and 100 mm length. A head of 10 cm of oil above the inlet of the capillary maintains a pressure difference across the capillary. The specific gravity of oil is 0.92. A volume of 300 cm3 of oil passes through the in 10s. What will be the viscosity of oil?
a) 5.68 * 10-4 poise
b) 5.98 * 10-4 poise
c) 5.68 * 10-5 poise
d) 5.98 * 10-5 poise
Answer: b
Explanation: p = ρgh
P = 0.92 * 981 * 1
P = 902.52 dyne/cm2
Now,
η = \(\frac{π p r^4 t}{8Vl} = \frac{[π*902.52*(0.15)^4*10]}{8*300*10}\) = 5.98 * 10-4poise.
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