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A bucket contains a mixture of two liquids A & B in the proportion 5 : 3. If 16 litres of the mixture is replaced by 16 litres of liquid B, then the ratio of the two liquids becomes 3 : 5. How much of the liquid B was there in the bucket?:

a) 25 litres
b) 15 litres
c) 18 litres
d) None of these

Answer: d
Explanation: Let bucket contains 5x and 3x of liquids A and B respectively.
When 16 litres of mixture are drawn off, quantity of A in mixture left:
$$\eqalign{ & {5x – {\frac{5}{8}} \times 16} = {5x – 10} \cr & {\text{Similarly quantity of B in mixture left}}, \cr & {3x – {\frac{3}{8}} \times 16} = {3x – 6} \cr & {\text{Now the ratio becomes,}} \cr & \frac{{ {5x – 10} }}{{ {3x – 6} }} = \frac{3}{5} \cr & 25x – 50 = 9x – 18 \cr & 16x = 32 \cr & x = 2 \cr & {\text{Quantity of liquid B initially}}, \cr & = 3 \times 2 = 6\,{\text{litres}} \cr} $$

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