A 2-wheel drive 35hp tractor has 1.5 rear wheel diameter. The engine runs at 1200 rev/min. the total reduction of speed is 30:1. Find the travelling speed of the tractor in km/h and the tractive force at each driving wheel.
a) 3.9925 KN
b) 2.1992 KN
c) 1.6784 KN
d) 4.1977 KN

Answer: d
Explanation: V_a = \(\frac{2πN*Dr*60}{2*30*1000}=\frac{2\pi*1.5*60*1200}{2*30*1000}\)=11.304
V_a = 3.11 m/s
P = F * v
F = \(\frac{P}{v}=\frac{35*746}{3.11}\)=8.3955 KN
Therefore, force on each wheel = \(\frac{8.3955}{2}\)=4.1977.