A 2-wheel drive 35 HP tractor has 1.5 m rear wheel diameter. The engine runs at 1200 rev/min. The total reduction of speed is 30:1. Find the travelling speed of the tractor in km/h and tractive force at each driving wheel.
a) 3.896 KN
b) 4.157 KN
c) 7.437 KN
d) 8.315 KN
Answer: b
Explanation: Naxle = 1200/30 = 40 rpm
Velocity = πNa * Da
= π * 40/60 * 1.5 = 3.14 m/s
Tractive force = P/V = \(\frac{(35*0.746)}{3.14}\) = 8.315 KN
Tractive at each driving wheel = 8.315/ 2
= 4.157 KN.
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