A three bottom 40 cm MB plough has a working depth of 15cm, draft is 1200 kg, field efficiency is 80%, and working speed is 4km/hr. What will be actual field capacity?
a) 0.384 ha/hr
b) 0.400 ha/hr
c) 0.200 ha/hr
d) 0.319 ha/hr
Answer: a
Explanation: Total cross-sectional area = 40*15*3 = 1800 cm2
Unit draft = 1200/1800 = 0.66 kg/cm2 = 64.68 KPa
Actual field capacity = Theoretical field capacity * field efficiency
= \(\frac{3*40*4*1000}{100*10000}*\frac{80}{100}\) = 0.384 ha/hr.
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