Total draft of four bottom, 40cm Mb plough when ploughing 17.5 cm deep at 5.5 km/hr speed is 1700. Field efficiency is 75%. Calculate the actual power requirement.
a) 24.73KW
b) 25.45KW
c) 23.39KW
d) 22.41KW
Answer: b
Explanation: Unit Draft = \(\frac{Total \, draft}{Area} = \frac{1700}{4*40*17.5}\) = 0.607 kg/cm2 *9.8 kPa = 59.48 kPa
Power requirement = \(\frac{1700*9.8*5.5*1000}{60*60}\)N.m/s = 25452.77 N.m/s = 25.45 KW.
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