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Determine the length of cross-belt of connecting two pulleys 4 m apart. The diameters of driving and driven pulleys are 1.25 m and 0.75 m respectively.

a) 12.36 m
b) 11.35 m
c) 14.28 m
d) 13.27 m

Answer: b
Explanation: L = 2C + \(\frac{[π(D1+D2)]}{2}+\frac{(D1+D2)^2}{4C} \)
= 2*4 + \(\frac{[π(1.25+0.75)]}{2}+\frac{(2)^2}{4*4}\) = 11.35 m

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