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What is the quantity of water which is to be circulated through the radiator, if diesel tractor developed 80 KW with coolant temperature difference 5.5° C?

a) 9.44 L/s
b) 10.01 L/s
c) 7.44 L/s
d) 8.44 L/s

Answer: c
Explanation: Q=A.V.Ma.Ca.∆ta
Q=80*0.58*0.161
Q=7.44 L/s.

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