a) 11340
b) 12750
c) 40
d) 320
Answer: a
Explanation: There 10 questions in part A out of which 8 question can be chosen as = 10C8
Similarly, 5 questions can be chosen from 10 questions of Part B as = 10C5
Hence, total number of ways,
$$\eqalign{
& { = ^{10}}{{\text{C}}_8}{ \times ^{10}}{{\text{C}}_5} \cr
& = \frac{{10!}}{{2! \times 8!}} \times \frac{{10!}}{{5! \times 5}} \cr
& = \left\{ {10 \times \frac{9}{2}} \right\} \times \left\{ {\frac{{10 \times 9 \times 8 \times 7 \times 6}}{{5 \times 4 \times 3 \times 2 \times 1}}} \right\} \cr
& = 11340 \cr} $$
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