a) 16C7 × 7!
b) 12C4 × 4C3 × 7!
c) 12C3 × 4C4
d) 11C4 × 4C3
Answer: b
Explanation: 4 consonants out of 12 can be selected in,12C4 ways.
3 vowels can be selected in 4C3 ways.
Therefore, total number of groups each containing 4 consonants and 3 vowels, = 12C4 × 4C3
Each group contains 7 letters, which can be arranging in 7! ways.
Therefore required number of words, = 12C4 × 4C3 × 7!
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