a) 12$$\pi$$ cm³
b) 15$$\pi$$ cm³
c) 16$$\pi$$ cm³
d) 20$$\pi$$ cm³

Answer: a
Explanation:

$$\eqalign{ & {\text{We have }}r = 3\,{\text{cm}}\,{\text{and}}\,h = 4\,{\text{cm}} \cr & {\text{Volume}} \cr & = \frac{1}{3}\pi {r^2}h \cr & = \left( {\frac{1}{3} \times \pi \times {3^2} \times 4} \right){\text{c}}{{\text{m}}^3} \cr & = 12\pi \,{\text{c}}{{\text{m}}^3} \cr} $$