a) $$\frac{7}{8}$$ of the weight of the original cube
b) $$\frac{8}{9}$$ of the weight of the original cube
c) $$\frac{63}{64}$$ of the weight of the original cube
d) $$\frac{511}{512}$$ of the weight of the original cube
Answer: d
Explanation: Volume of the bigger cube = (83) cm3 = 512 cm3
Volume of the cut-out cube = (13) cm3 = 1 cm3
Volume of the remaining portion = (512 – 1) cm3 = 511 cm3
$$\frac{{{\text{Weight of the remaining portion}}}}{{{\text{Weight of the original cube}}}}$$ $$ = \frac{{511}}{{512}}$$
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