a) 5 sec
b) 6 sec
c) 7 sec
d) 10 sec
Answer: b
Explanation:
$$\eqalign{
& {\text{Speed}}\,{\text{of}}\,{\text{train}}\,{\text{relative}}\,{\text{to}}\,{\text{man}} = \left( {60 + 6} \right)\,{\text{km/hr}} \cr
& = 66\,{\text{km/hr}} \cr
& = {66 \times \frac{5}{{18}}} \,{\text{m/sec}} \cr
& = {\frac{{55}}{3}} \,{\text{m/sec}} \cr
& {\text{Time}}\,{\text{taken}}\,{\text{to}}\,{\text{pass}}\,{\text{the}}\,{\text{man}} \cr
& = {110 \times \frac{3}{{55}}} {\text{sec}} = 6\,{\text{sec}} \cr} $$.
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