a) 60.48
b) 64.86
c) 80.64
d) 82.38
Answer: c
Explanation:
$$\eqalign{
& {\text{Length of train}} = 280 m \cr
& {\text{Length of platform}} \cr
& {\text{ = (3}} \times {\text{280) m = 840m}} \cr
& {\text{Speed of train}} \cr
& {\text{ = }}\left( {\frac{{280 + 840}}{{50}}} \right)m/\sec \cr
& = \frac{{1120}}{{50}}m/\sec \cr
& = \left( {\frac{{1120}}{{50}} \times \frac{{18}}{5}} \right)km/hr \cr
& = 80.64\,km/hr \cr} $$
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