a) 2 : 5
b) 3 : 5
c) 4 : 5
d) 5 : 2
Answer: d
Explanation:
$$\eqalign{
& = {\text{3A}} = {\text{5B and 4B}} = {\text{6C}} \cr
& \frac{{\text{A}}}{{\text{B}}} = \frac{5}{3}{\text{ and }}\frac{{\text{B}}}{{\text{C}}} = \frac{6}{4} = \frac{3}{2} \cr
& \frac{{\text{A}}}{{\text{C}}} = \left( {\frac{{\text{A}}}{{\text{B}}} \times \frac{{\text{B}}}{{\text{C}}}} \right) = \frac{5}{3} \times \frac{3}{2} = \frac{5}{2} \cr
& {\text{A}}:{\text{C}} = {\text{5}}:{\text{2}} \cr} $$
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