If x2 + 4y2 = 4xy, then x : y is –
a) 1 : 1
b) 1 : 2
c) 2 : 1
d) 1 : 4
Answer: c
Explanation:
$$\eqalign{
& = {x^2} + 4{y^2} = 4xy \cr
& \Rightarrow {x^2} – 4xy + 4{y^2} = 0 \cr
& \left( {x – 2{y^2}} \right) = 0 \cr
& x = 2y \cr
& \frac{x}{y} = 2 \cr
& \Rightarrow x:y = 2:1 \cr} $$
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