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Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

a) 10
b) 12
c) 14
d) 16

Answer: c
Explanation: Part filled in 2 hours = $$\frac{2}{6}$$ = $$\frac{1}{3}$$
Remaining part = $$ {1 – \frac{1}{3}} $$  = $$\frac{2}{3}$$
(A + B)’s 7 hour’s work = $$\frac{2}{3}$$
(A + B)’s 1 hour’s work = $$\frac{2}{{21}}$$
C’s 1 hour’s work = {(A + B + C)’s 1 hour’s work} – {(A + B’s 1 hour’s work}
$$\eqalign{ & = {\frac{1}{6} – \frac{2}{{21}}} \cr & = \frac{1}{{14}} \cr} $$
C alone can fill the tank in 14 hours

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