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A pipe can fill a tank in 3 hours. There are two outlet pipes from the tank which can empty it in 7 and 10 hours respectively. If all the three pipes are opened simultaneously, then the tank will be filled in –

a) 8 hours
b) 9 hourss
c) 10 hours
d) 11 hours

Answer: d
Explanation: Net part filled in 1 hour
$$\eqalign{ & {\text{ = }}\frac{1}{3} – \left( {\frac{1}{7} + \frac{1}{{10}}} \right) \cr & = \frac{1}{3} – \frac{{17}}{{70}} \cr & = \frac{{19}}{{210}} \cr} $$
The tank will be filled in $$\frac{{210}}{{19}}$$  hours i.e.
$$\eqalign{ & {\text{= 11}}\frac{1}{{19}}{\text{ hours}} \cr & \cong 11\,{\text{hours }} \cr} $$

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