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At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years ?

a) 6.5%
b) 4.5%
c) 6%
d) 7.5%

Answer: c
Explanation:
$$\eqalign{ & {\text{A = P }}{\left( {1 + \frac{{\text{R}}}{{100}}} \right)^n} \cr & 1348.32 = 1200{\left( {1 + \frac{{\text{R}}}{{100}}} \right)^2} \cr & \frac{{134832}}{{120000}} = {\left( {1 + \frac{{\text{R}}}{{100}}} \right)^2} \cr & \frac{{231525}}{{200000}} = {\left( {1 + \frac{{\text{R}}}{{100}}} \right)^2} \cr & \frac{{2809}}{{2500}} = {\left( {1 + \frac{{\text{R}}}{{100}}} \right)^2} \cr & {\left( {\frac{{53}}{{50}}} \right)^2} = {\left( {1 + \frac{{\text{R}}}{{100}}} \right)^2} \cr & \frac{{53}}{{50}} = 1 + \frac{{\text{R}}}{{100}} \cr & {\text{R}} = {\text{ 6% }} \cr} $$

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