a) $${\text{Rs}}{\text{.}}\,\frac{{P{R^2}}}{{100}}$$
b) $${\text{Rs}}{\text{.}}\,\frac{{2PR}}{{100}}$$
c) $${\text{Rs}}{\text{.}}\,\frac{{PR}}{{100}}$$
d) $${\text{Rs}}{\text{.}}\,\frac{{P{R^2}}}{{{{\left( {100} \right)}^2}}}$$
Answer: d
Explanation:
$$\eqalign{
& {\text{S}}{\text{.I}}{\text{. = Rs}}{\text{.}}\left( {\frac{{P \times R \times 2}}{{100}}} \right) \cr
& \,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{.}}\left( {\frac{{2PR}}{{100}}} \right) \cr
& {\text{C}}{\text{.I}}{\text{. = Rs}}{\text{.}}\left[ {P \times {{\left( {1 + \frac{R}{{100}}} \right)}^2} – P} \right] \cr
& \,\,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{.}}\left[ {\frac{{P{R^2}}}{{{{\left( {100} \right)}^2}}} + \frac{{2PR}}{{100}}} \right] \cr
& \therefore {\text{Difference}} \cr
& {\text{ = Rs}}{\text{.}}\left[ {\left\{ {\frac{{P{R^2}}}{{{{\left( {100} \right)}^2}}} + \frac{{2PR}}{{100}}} \right\} – \frac{{2PR}}{{100}}} \right] \cr
& = {\text{Rs}}{\text{.}}\left[ {\frac{{P{R^2}}}{{{{\left( {100} \right)}^2}}}} \right] \cr} $$
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