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The average of the ages of a man and his daughter is 34 years. If the respective ratio of their ages four years from now is 14 : 5,what is daughter’s present age ?

a) 12 years
b) 10 years
c) 18 years
d) 16 years

Answer: d
Explanation: Average age of man and his daughter = 34 years
Their total age = (34 × 2) years = 68 years
Let man’s age be x years,
Then daughter age = (68 – x) years
$$\eqalign{ & \therefore \frac{{x + 4}}{{68 – x + 4}} = \frac{{14}}{5} \cr & \Rightarrow 5\left( {x + 4} \right) = 14\left( {72 – x} \right) \cr & \Rightarrow 5x + 20 = 1008 – 14x \cr & \Rightarrow 19x = 988 \cr & \Rightarrow x = 52 \cr} $$
∴ Daughter’s present age
= (68 – 52) years
= 16 years

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