a) 15
b) $$15\frac{1}{5}$$
c) 14
d) $$14\frac{1}{5}$$
Answer: b
Explanation: Average of 12 numbers = 15
Total of 12 numbers = 15 × 12 = 180
Average of first two number = 14
Total of first two number = 14 × 2 = 28
Total of remaining ten numbers = 180 – 28 = 152
Required average of remaining ten number
$$\eqalign{
& = \frac{{152}}{{10}} \cr
& = \frac{{76}}{5} \cr
& = 15\frac{1}{5} \cr} $$
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