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A population of variety of tiny bush in an experiment field increased by 10% in the first year, increased by 8% in the second year but decreased by 10% in third year. If the present number of bushes in the experiment field is 26730, then the number of variety of bushes in beginning was:

a) 35000
b) 27000
c) 25000
d) 36000

Answer: c
Explanation: Let the number of bushes originally be 100
Number of bushes after one year
100 ==10% (↑) ==> 110
After second year it becomes
110 ==8%(↑) ==> 118.8
After third year,
118.8 ==8%(↓)==> 109.3
Now,
109.3 = 26730
1 = $$\frac{{26730}}{{109.3}}$$
So, 100 = $$\frac{{26730}}{{109.3}} \times 100$$    = 25000
Number of bushes originally was 25000

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