a) 5 km
b) 15 km
c) 25 km
d) 35 km
Answer: b
Explanation:
$$\eqalign{
& {\text{Speed of first Jogger}} \cr
& = {\frac{{ {x – 1} }}{{42}}} \times 60\,{\text{kmph}} \cr
& {\text{Speed of }}\,{2^{nd}}\,{\text{jogger}} \cr
& = {\frac{{ {x – 2} }}{{52}}} \times 60\,{\text{kmph}} \cr
& {\text{Then}}, \cr
& {\frac{{x – 2}}{{{s_b}}}} – {\frac{{x – 1}}{{{s_b}}}} \cr
& \cr} $$
Now, check option one by one which gives us that option (b) is correct.
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