a) 50 s, 1000 m
b) 65 s, 1150 m
c) 65 s, 1300 m
d) 45 s, 1050 m
Answer: b
Explanation: Initial speed of the police = 10 m/s
Increased speed of the Police = 20 m/s
Speed of the thief = 15 m/s
Initial difference between speed of thief and police = 250 m
After 5 seconds difference between thief and police = 200 + (5 × 10) = 250 m
The time required by police to catch the thief = $$\frac{{250}}{5}$$ = 50 s
Total time = 50 + 15 = 65 s
Total distance = 1000 + (15 × 10) = 1150 m
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