A runs $$\frac{7}{4}$$ times as fast as B. If A gives B a start of 300 m, how far must the winning post be if both A and B have to end the race at same time?
a) 1400 m
b) 700 m
c) 350 m
d) 210 m
Answer: b
Explanation: If A runs 7/4 times as fast as B
A : B = 7 : 4
Let x be the constant ratio
A : B = 7x : 4x
The difference is 300m
7x – 4x = 300
3x = 300
x = 100m
The winning post is the distance A has to run
A = 7x = 7(100) = 700 m
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