A train met with an accident 120 km from station A. It completed the remaining journey at $$\frac{5}{6}$$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
a) 100 km/h
b) 12 km/h
c) 60 km/h
d) 50 km/h
Answer: c
Explanation: A ____100 km____ P1 ________300 km_____ P2 ____X______ B
If speed becomes $$\frac{5}{6}$$ then time taken will be $$\frac{6}{5}$$ of original time.
Thus, extra time = 2 hour
$$\frac{1}{5}$$ = 2 hour
Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.
It means It covers 300 km distance in 5 hours.
Speed = $$\frac{{300}}{5}$$ = 60 km/h
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