a) 30 kmph
b) $$32\frac{8}{{11}}$$ kmph
c) $$35\frac{8}{{11}}$$ kmph
d) 32 kmph
Answer: c
Explanation: Let the speed of train = x km/ hr
Length of train = 300 metres
Their relative speed in same direction
= (x – 3) km/hr
According to the question,
$$\frac{{\left( {300 + 0} \right)m}}{{\left( {x – 3} \right) \times \frac{5}{{18}}m/s}} = 33$$
[Here man’s length is 0 metre]
$$\eqalign{
& \frac{{100 \times 18}}{{5x – 15}} = 11 \cr
& 1800 = 55x – 165 \cr
& 55x = 1965 \cr} $$
∴ Speed of the train = $$\frac{{1965}}{{55}}$$ = $$35\frac{8}{{11}}$$ kmph
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